Assertion : Aniline does not undergo Friedel- | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Aniline is a Lewis base due to the lone pair of electrons on the nitrogen atom of the $-NH_2$ group.Friedel-Crafts reaction requires $AlCl_3$ as a

Vedclass · Accepted Answer

If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.

Vedclass · Answer

(A) Aniline is a Lewis base due to the lone pair of electrons on the nitrogen atom of the $-NH_2$ group.Friedel-Crafts reaction requires $AlCl_3$ as a Lewis acid catalyst.When aniline reacts with $AlCl_3$,it forms a salt (an acid-base adduct) where the nitrogen atom coordinates with the aluminum atom.This results in the nitrogen atom acquiring a positive charge,which acts as a strong deactivating group for the benzene ring,thereby inhibiting the electrophilic substitution reaction required for Friedel-Crafts alkylation or acylation.Therefore,both the Assertion and the Reason are correct,and the Reason is the correct explanation for the Assertion.

Assertion : Aniline does not undergo Friedel-Crafts reaction.
Reason : $-NH_2$ group of aniline reacts with $AlCl_3$ (Lewis acid) to give acid-base reaction.

Similar Questions

Identify $Y$ in the following reaction sequence:
$CH_3-CH(CH_3)-CH_2-CONH_2$ $\xrightarrow{KOBr(aq)} X$ $\xrightarrow{NaNO_2/HCl(aq)} Y$

Which of the following compounds gives an even number of Hoffmann's exhaustive methylation and elimination cycles?

Explain the basicity of aromatic amines.

Which of the following statements is correct?

Identify the major product formed in the following reaction: $C_6H_5NH_2 + CHCl_3 + 3KOH \to ?$

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Assertion : Aniline does not undergo Friedel-Crafts reaction.Reason : $-NH_2$ group of aniline reacts with $AlCl_3$ (Lewis acid) to give acid-base reaction.